Three coins are tossed once. Find the probabi | vedclass

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(C) When three coins are tossed once,the sample space is $S = \{HHH, HHT, HTH, THH, HTT, THT, TTH, TTT\}$.Therefore,the total number of outcomes is $n

Vedclass · Accepted Answer

$7/8$

Vedclass · Answer

(C) When three coins are tossed once,the sample space is $S = \{HHH, HHT, HTH, THH, HTT, THT, TTH, TTT\}$.Therefore,the total number of outcomes is $n(S) = 8$.Let $E$ be the event of getting at most $2$ heads. This means we exclude the case of $3$ heads $(HHH)$.The favorable outcomes are $E = \{HHT, HTH, THH, HTT, THT, TTH, TTT\}$.Thus,$n(E) = 7$.The probability is $P(E) = \frac{n(E)}{n(S)} = \frac{7}{8}$.

Three coins are tossed once. Find the probability of getting at most $2$ heads.

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